Consider the line that passes through the point (3, -2) and has a slope of 2.?

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Consider the line that passes through the point (3, -2) and has a slope of 2. Part 1: Write the equation of this line using point-slope form. (2 points) Part 2: Using your ...show more
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  • Bif answered 3 years ago
Part 1: Plug into point slope formula: y-y1=m(x-x1)
y+2=2(x-3)

Part 2: Solve for y
y+2=2x-6
y=2x-8

Part 3: Rearrange to standard form
2x-y-8=0
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  • Spaceman Spiff answered 3 years ago
    The line passes through the point (3,-2), and has a slope of 2

    1. The formula for the point-slope form is given by y - y1 = m(x - x1), where the point is (x1,y1) and the slope is "m":

    y - (-2) = 2(x - 3)

    Simplifying:

    y + 2 = 2(x - 3)


    2. Slope-intercept form is given by y = mx + b, where "m" is the slope and "b" is the y-intercept:

    y + 2 = 2(x - 3)

    y + 2 = 2x - 6

    y = 2x - 8


    3. Standard form is given by Ax + By = C, where A, B, and C are constants:

    y = 2x - 8

    y - 2x = -8

    In this case, A = 1, B = -2, and C = -8.
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  • Nerd Nerdiness answered 3 years ago
    y - (-2) = 2(x-3)

    y + 2 = 2x-6
    y = 2x - 6 -2
    y = 2x-8
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  • Edward answered 3 years ago
    y-y1=m(x-x1) m= slope. y+2=2(x-3) now set it up in slope intercept form by multiplying the 2 to the x and the negative 3 to get 2x-6. now subtract the 2 from the left side of the equation. You now have 2x-8.
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