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(2, 3) and (4, 6)
slope = (36)/(2+4) = 3/2
From the rightmost point (the first one), since the line decreases 3 for every 2 increase in x, the yintercept is at the origin. 
the formula is Y2Y1 divided by X1X2
which would be: 63 divided by 4  2
3 divided by 2
slope= 1.5 the slope is negative 
3/2

63 over4(2)

Slope = (y2y1)/(x2x1)
= (36)/(24)
= 3/2
Equation = y = 3/2x 
(y2y1)/(x2x1)=m
y1=3
y2=6
x1=2
x2=4
(63)/[4(2)]
(63)/(4+2)
3/2
1.5=m
which is the slope
Find the slope of the line containing the given pair of points.?
Find the slope of the line containing the given pair of points. If the line is undefined, state so. Please be sure to show all of your work. (2, 3) and (4, 6)
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