How do you find concentration?
When 7.6 g of NaCl(s) is added to a 250 mL solution of 0.78 M silver nitrate (AgNO3), the chloride ions combine with silver ions, and precipitate as AgCl(s) at the bottom of the solution. What concentration of Ag+ ions remains dissolved in the water?
- Steve OLv 71 decade agoFavorite Answer
(7.6 g NaCl) divided by (a molar mass of 58.44 g/mol) = 0.130 moles of NaCl
0.250 litres @ 0.78 mol / litre = 0.195 moles of AgNO3
by the reaction:
1 NaCl & 1 AgNO3 -- 1 AgCl & 1 NaNO3
0.130 moles of NaCl reacts with an equal number of moles of AgNO3: 0.130 moles of AgNO3
0.195 moles of AgNO3 - 0.130 moles of AgNO3 reacted = 0.065 moles AgNO3 remain
0.065 moles AgNO3 / 0.250 litres = 0.26 Molar AgNO3
0.26 Molar AgNO3
0.26 Molar Ag+ ion