Please explain how to find the margin of error?
Find the margin of error for a survey that has a given sample size. Round your answers to the nearest tenth of a percent.
(if you could explain your answer that would help tremendously)
- LindsayLv 41 decade agoFavorite Answer
margin of error is the z value times the standard deviation divided by the square root of the sample size. Lol sorry that's in words instead of written formula. But the z value is taken from the amount that is in the tail, so if there is .025 in the left tail, you go to the z table (negative values) and find .025 in the area part. I believe it is -1.96...either that or -2.33....I don't remember, but anyways you take that number and that is your z. But disregard the negative sign because ultimately you are taking the average and adding/subtracting the margin of error.
If your sample size is less than 30 you need to use the t-table. For that, you need to know the df, which is n-1 or the sample size minus one; then take the amount in the tail, for example, .025, and see where they cross. That is your t-value which you then multiply by the same thing you multiplied z in the first time...standard deviation divided by the square root of the sample size.
Hope this helped, Good luck :)
- Keun WoongLv 71 decade ago
Is this for proportion or mean?
E = z* sqrt(p^ q^ /n)
For mean with sigma:
E = z* sigma/sqrt(n)
For mean without sigma:
E = t* s/sqrt(n)