A tiger leaps horizontally from a 6.1 m high rock with a speed of 3.9 m/s. How far from the base of the rock w?

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Update : How far from the base of the rock will she land?***
Best Answer
  • Cool answered 3 years ago
vertical component
s=ut+1/2at^2
6.1=0+1/2x9.8x t^2
t^2=6.1/4.9=1.25
t=under root1.25=1.12s
horizontal component
dist covered in 1.12s
3.9x1.12=4.368m
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Other Answers (1)

  • Technobuff answered 3 years ago
    A tigress.
    Time to drop 6.1m = sqrt. (2h/g), = 1.116 secs.
    (1.116 x 3.9) = 4.35m. from the base of the rock.
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