# oxygen chemistry question?

A reaction should yield 4.41 grams of oxygen. What do you expect the volume to be @ 21 degrees celcius and .916 atm?

### 1 Answer

- 9 years agoFavorite Answer
This problem gives you...

-Grams (that can be converted to moles)

-Temperature in Celsius

-Atmosphere in atm

These 3 are HUGE hints to use PV = nRT.

And since you want to find Volume, you can re-arrange this equation to...

V = nRT/P

With this newly rearranged equation, you can find V, by plugging in each of the values given. Make note that since R = 0.0821 L*atm/mol*K in this situation, temperature must also be in Kelvins.

T = 21 C + 273 K

T = 294 K

Also, we must change 4.41 grams oxygen to moles oxygen, as stated earlier:

4.41 grams O2 x (1 mole O2/32 grams O2) = 0.138 moles O2

NOW, plug your information into the equation:

V = nRT/P

= [(0.138 moles O2)(0.0821 L*atm/mol*K)(294K)] / 0.916 atm

= 8.38 L O2

Please make sure to check my work to make sure I have every number written down correctly.

Good luck!