oxygen chemistry question?
A reaction should yield 4.41 grams of oxygen. What do you expect the volume to be @ 21 degrees celcius and .916 atm?
- 9 years agoFavorite Answer
This problem gives you...
-Grams (that can be converted to moles)
-Temperature in Celsius
-Atmosphere in atm
These 3 are HUGE hints to use PV = nRT.
And since you want to find Volume, you can re-arrange this equation to...
V = nRT/P
With this newly rearranged equation, you can find V, by plugging in each of the values given. Make note that since R = 0.0821 L*atm/mol*K in this situation, temperature must also be in Kelvins.
T = 21 C + 273 K
T = 294 K
Also, we must change 4.41 grams oxygen to moles oxygen, as stated earlier:
4.41 grams O2 x (1 mole O2/32 grams O2) = 0.138 moles O2
NOW, plug your information into the equation:
V = nRT/P
= [(0.138 moles O2)(0.0821 L*atm/mol*K)(294K)] / 0.916 atm
= 8.38 L O2
Please make sure to check my work to make sure I have every number written down correctly.