an olympic runner leaps over a hurdle the acceleration of gravity is 9.81 if the runners initial verticle spe?

an olympic runner leaps over a hurdle the acceleration of gravity is 9.81 if the runners initial verticle speed is 2 m/s how much will the runners center of mass be raised during the jump? answer in m.

1 Answer

Relevance
  • 1 decade ago
    Favorite Answer

    height=initial velocity times time --1/2gravity times time squared

    h=2t-4.905t^2

    you need to find the time when the velocity is zero

    0=v-at

    t=.204 seconds

    plug it back in to the first equation

    h=2(.204)-4.905(.204)^2

    h=.204 meters

Still have questions? Get your answers by asking now.