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# an olympic runner leaps over a hurdle the acceleration of gravity is 9.81 if the runners initial verticle spe?

an olympic runner leaps over a hurdle the acceleration of gravity is 9.81 if the runners initial verticle speed is 2 m/s how much will the runners center of mass be raised during the jump? answer in m.

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- 1 decade agoFavorite Answer
height=initial velocity times time --1/2gravity times time squared

h=2t-4.905t^2

you need to find the time when the velocity is zero

0=v-at

t=.204 seconds

plug it back in to the first equation

h=2(.204)-4.905(.204)^2

h=.204 meters

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