math problem please help im stupid....?

a band competition awards prizes to the top three schools. If 8 schools are entered how many ways can 3 schools be chosen?

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  • 9 years ago
    Favorite Answer

    8 schools

    3 places: 1st place, 2nd place, 3rd place.

    So it is possible that one of the 8 schools can take 1st place. If one of the 8 takes 1st place, that leave 7 available to take 2nd place. If one of the 7 remaining is chosen for 2nd place, that leaves 6 schools that could place 3rd.

    8 * 7 * 6 = number of combinations.

    or you can do it the hard way and name the 8 schools A,B,C,D,E,F,G,H and list the combinations:

    ABC ABD ABE ABF ABG ABH

    ACB ACD ACE ACF ACG ACH

    ADB ADC ADE ADF ADG ADH

    AEB AEC AED AEF AEG AEH

    AFB AFC AFD AFE AFG AFH

    ....

    etc...

    and count up the combinations.

  • stonge
    Lv 4
    3 years ago

    Hooke's regulation says that F = -kx (the place F is stress x is extension and ok is a relentless) on your occasion you in uncomplicated terms could carry out a normal ratio calculation. If the ratio of the weights is 3/2 then the ratio of the extensions stands out as the comparable. 60/40 = x/6 x = 9 subsequently the spring with a 60lb weight could stretch 9 inches.

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