take the natural log of a natural log?

Question

ln(lnX^1/2)

I have to take the natural log of natural log of the square root (x^1/2) of x.

HELP!

Answer 1

Favorite Answer

ln ln x^(1/2)

= ln (ln x)/2

= ln ln x - ln 2

Answer 2

ln(lnX^1/2)=ln[(1/2)ln(x)]

=ln[ln(x)] -ln(2)