Currents in a Metal Wire and Shell.?

Follow
  • Follow publicly
  • Follow privately
  • Unfollow
A solid conductor with radius 0.8mm is supported by insulating disks on the axis of a conducting cylindrical shell with inner radius 9.1mm and outer radius 9.9mm . The central ...show more
Best AnswerAsker's Choice
  • ? answered 4 years ago
Current density(J) is the current(I) per area(A).
So J=I/A, however your A is the area of the circle. So we use the equation pi*r^2=A
J=I/pi(r^2)
Its in mm so I will change it just by dividing by a thousand.

1) The inner wire has a radius of 0.8/1000, so J=5.4/(pi*(0.8/1000)^2

2) For the outer shell is J=1.9/(pi*[(9.9/1000)^2-(9.1/1000)^2])

Asker's rating & comment

5 out of 5
thanks
  • Rate
  • Comment
Sign In 

to add your answer

No other answers

Who is following this question?

    %
    BEST ANSWERS
    Member Since:
    Points: Points: Level
    Total Answers:
    Points this week:
    Follow
     
    Unfollow
     
    Block
     
    Unblock