PROJECTILE MOTION please answer those questions with details thank u?
please answer those questions with details thank u
these Q are related to the projectile motion physic
1)Derive the following two equations:t:√2h/g, and R=v.sin2θ/g
2)Does a change in the initial speed change the time of flight?if so, how?
- trueproberLv 79 years agoFavorite Answer
Hello benalia, let us imagine a body is thrown with a initial velocity v in a direction inclined at an angle θ.
Then there exists the non changing component v cosθ and the decreasing component v sinθ. By using v = u - g t, t = u/g as v becomes 0 at maximum height. So the time to reach the max height
t = v sinθ / g. So the total time for the flight called as time of flight = 2 v sinθ /g
For max height we use the formula, v^2 = u^2 - 2gs. Here s = h max u = v sinθ and v = 0
HEnce h max = v^2 sin^2 θ / 2g.
In case to find the range R, the constant velocity v cosθ would make a distance covered during the time of flight. THat is known as range R.
SO R = v cosθ * 2 v sinθ / g = v^2 sin 2θ / g.
Hence what you have given is not suitable for projectile motion. They are t = √2h/g and R = v.sin2θ/g
2) Sure. TIme of flight would change as t of flight = 2 u sinθ/g and t depends on u the initial speed of projection.
- vastineLv 43 years ago
"The ball is laid low with air resistance." it particularly is a needed component to the question. not in basic terms does this mean that the horizontal component to the linked fee will drop to 0, yet this additionally potential that, for the period of its fall, the ball will at last attain its terminal velocity. it particularly is because of the fact the rigidity of air drag because of its velocity in direction of earth negates the rigidity of gravity, meaning there is no internet rigidity and no internet acceleration.