? asked in Science & MathematicsMathematics · 9 years ago

Find the value of K for which the roots are real & equal in each of the following equation: k^2x^2 - 2(2k - 1?

Find the value of K for which the roots are real & equal in each of the following equation:

k^2x^2 - 2(2k - 1)x + 4 =0

plz help me out show method

2 Answers

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  • 9 years ago
    Best Answer

    The given equation is a quadratic equation.

    If we compare it with the standard form of quadratic equation i.e. ax^2+bx+c=0,

    a=k^2, b= -2(2k-1) = (-4k+2) and c=4.

    The roots of a quadratic equation are real and equal if, b^2-4ac=0.

    So, for given equation, the roots will be real and equal if,

    (-4k+2)^2-4*k^2*4=0

    On expansion,

    16k^2-16k+4-16k^2=0

    -16k+4=0

    16k=4

    k=4/16

    k=1/4

  • 9 years ago

    (-4k+2)^2-4*k^2*4=0

    On expansion,

    16k^2-16k+4-16k^2=0

    -16k+4=0

    16k=4

    k=4/16

    k=1/4

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