# Find the value of K for which the roots are real & equal in each of the following equation: k^2x^2 - 2(2k - 1?

Find the value of K for which the roots are real & equal in each of the following equation:

k^2x^2 - 2(2k - 1)x + 4 =0

plz help me out show method

### 2 Answers

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- 9 years agoBest Answer
The given equation is a quadratic equation.

If we compare it with the standard form of quadratic equation i.e. ax^2+bx+c=0,

a=k^2, b= -2(2k-1) = (-4k+2) and c=4.

The roots of a quadratic equation are real and equal if, b^2-4ac=0.

So, for given equation, the roots will be real and equal if,

(-4k+2)^2-4*k^2*4=0

On expansion,

16k^2-16k+4-16k^2=0

-16k+4=0

16k=4

k=4/16

k=1/4

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