Probability: A bridge hand in which there is no card higher than a 9 is called a Yarborough after the Earl who?

A bridge hand in which there is no card higher than a 9 is called a Yarborough after the Earl who liked to bet at 1,000 to 1 that your bridge hand would have a card that was 10 or higher. What is the probability of a Yarborough when you draw 13 cards out of a deck of 52.

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  • 10 years ago
    Favorite Answer

    prob is best described as #of outcomes that satisfy condition/# of possible outcomes

    assuming that A is high (I dont play bridge) then there are 32 cards lower than a 10 which means that there are 32!/(13!*(32-13)!) ways of making this Yarborough. this is read 32 choose 13

    the total possible number of outcomes is 52!/(52!*(52-13!)) (or 52 choose 13)

    p(Yarborough)=[32!/(13!*(32-13)!)]/[52!/(52!*(52-13!))]

    You prob. know that x!=x*(x-1)*(x-2)*....(x-x+1) or you wouldnt be asking a prob. question like this but I thought Id point it out

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  • boven
    Lv 4
    3 years ago

    Yarborough Bridge

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  • 10 years ago

    13C9

    Source(s): my brain
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