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- 螞蟻雄兵Lv 71 decade agoFavorite Answer
Let y=ln(x+√x).Find dx/dy in terms of x. Soly=ln(x+√x)dy/dx=dln(x+√x)/dx=[dln(x+√x)/d(x+√x)]*[d(x+√x)/dx]=[1/(x+√x)]*[1+1/(2√x)]=[1/(x+√x)]*[(2√x+1)/(2√x)]=[1/(x+√x)]*[(2√x+1)/(2√x)]=[(2√x+1)/(2x√x+2x)]dx/dy=2x(√x+1)/(2√x+1)

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