What is the value of K c in L/mol at this temperature ?
2NO(g) + Cl2(g) ↔ 2NOCl(g)
The above reaction has a value of K p equal to 1.42× 103 atm−1 at a 25.0 oC. What is the value of K c in L/mol at this temperature ?
- Dr.ALv 79 years agoFavorite Answer
delta n = 2 - 2 - 1 = -1
T = 298 K
1.42 x 10^3 = Kc ( RT)^delta n = Kc ( 0.08206 x 298)^-1 = Kc x 0.0409
Kc = 3.47 x 10^4
- jesseLv 43 years ago
you will use purely this eqn to resolve each and each question PV = nRT all you're able to desire to do is to make powerful that the contraptions are familiar P might desire to be in Pa a million atm = one hundred and one 325 pascals V might desire to be in m^3 a million L = a million dm^3 a million dm^3 = (10^-a million)^3 m^3 T might desire to be in ok Temp in ok = Temp in C + 273 R (gas consistent)= 8.31 Pa m^3/mol ok N.B. for techniques given with mass use mass in g = molar mass in g/mol *mol purely follow the above to calculate the ans on your questions, it particularly is as eadsy as that. choose this permits.