create a quadratic function with a minimum point, two positive real roots, and a y-intercept of 12.?
create a quadratic function with a minimum point, two positive real roots, and a y-intercept of 12.
a) give function in standart form of the polynomial
b) solve for the zeros by using the quadratic formula
c) give the linear factored form
- Rita the dogLv 710 years agoFavorite Answer
y = (x-1)(x-2) has two positive real roots, but its value at x=0 is 2, so multiply by 6 and get y = 6(x-1)(x-2) for a quadratic function with two real roots and y-intercept 12. It opens upward, since coefficient of x^2 is positive, and so it has a minimum point.
Edit: an easier example is y = (x-3)(x-4) which has all the required properties without adjustment.