Need help solving word problems. Algebra 1. Please Help!!!?

1.Jill travels to work in 1 hr and 30 min, while Jane travels to work in 1 hr and 20 min. Jane drives 5 mph faster to work than Jill. They botth drive the same distance to work. How fast does Jill drive, and how far do they both drive to work?

2.John leaves home traveling to the next city at 50 mph. His sister Joann leaves home 30 min later, traveling the same route as John, but John travels 65 mph. How long will it take Joann to catch up with John?

Please explain and solve each one thanks!!! First person to respond with the Best answer gets Best Answer.

2 Answers

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  • EC
    Lv 4
    1 decade ago
    Favorite Answer

    1.Jill travels to work in 1 hr and 30 min, while Jane travels to work in 1 hr and 20 min. Jane drives 5 mph faster to work than Jill. They botth drive the same distance to work. How fast does Jill drive, and how far do they both drive to work?

    Jill's travel time = 1.5 hours

    Jill's speed = x mph

    Jane's travel time = 1.333 hours

    Jane's speed = x+5 mph

    Distance = y miles

    Jill

    x mph * 1.5 hrs = y miles

    Jane

    (x+5) mph * 1.333 hrs = y miles

    x*1.5 = (x+5) * 1.33

    1.5x = 1.33(x+5)

    Divide both sides by 1.33

    1.13x = x+5

    Subtract x from both sides

    .13x = 5

    Divide both sides by .13

    x = 38.5 mph <---Jill's speed

    x+5 = 43.5 <---Jane's speed

    y = 38.5 * 1.5 = 57.75 miles <---Distance both travel

    2.John leaves home traveling to the next city at 50 mph. His sister Joann leaves home 30 min later, traveling the same route as John, but John travels 65 mph. How long will it take Joann to catch up with John?

    I'm assuming you mean Joann travels 65 mph

    John's speed = 50 mph

    John's distance when Joann catches up = x miles

    John's travel time when Joann catches up = y hours

    x miles = 50 mph * y hours

    Joann's speed = 65 mph

    Joann's distance travelled when she catches up to John = x miles

    Joann's travel time when she catches up to John = y-.5 hours

    x miles = 65 * (y-.5 hours)

    50*y = 65*(y-.5)

    Divide both sides by 65

    .77y = y-.5

    Subtract y from both sides

    -0.23y = -.5

    Divide both sides by -.23

    y = 2.17 hours

    y-.5 = 1.67 hours (1 hour, 40 mins) <--- how long it takes for Joann to catch up to John

  • 1 decade ago

    The problem is the fact that Jane and Jill are driving

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