? asked in Science & MathematicsMathematics · 1 decade ago

Two Questions!! Easy 10 Points!!! CLICK HERE!!!!!!!!!!!!!!!!!!!!!!?

1.

-7y - 17 > 11

Part 1: Solve the inequality above.

Part 2: Describe the graph of the solution.

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2.

16 < 3x + 1 < 4

Part 1: Solve the inequality above.

Part 2: Describe the graph of the solution.

3 Answers

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  • 1 decade ago
    Favorite Answer

    1. the inequation is

    - 7y - 17 >11

    - 7y > 16

    - y >16/7

    y <- 16/7

    so inequation will be satisfied for for any y >-16/7 for any real value of x...take any value of x and any value of y such that y > -16/7 , plot them on a graph paper ,then you will get an area or section..that's the required graph.

    clearly the graph will be a section (area) which will lie above the straight line y = -16/7 and wouldn't touch (x,-16/7)..the section can exist till x exists.

    2) similarly the inequation

    16 < 3x + 1 < 4

    15<3x<3

    5<x<1

    clearly the inequation is satisfied for any value of x which lies in this open interval (and for any real value of y)

    now take any value of y (real) and take any value of x which lies in that interval. plot them on a graph paper..you will get a graph (a section) which doesn't touch x = 1 and x = 5. this is the required graph.

  • 1 decade ago

    -7y-17>11

    -7y-17+17>11+17

    -7y>28

    -7y/-7<28/-7

    y<-4 anything that is <-4 would be shaded for the complete solution with a dotted line at

    y=-4

    16<3x+1< 4 16<3x+1-1<4 16-1<3x+1-1<4-1 15<3x< 3 5<x<1 anything between x<5<1 would be shaded excluding 5 and 1

  • Ed I
    Lv 7
    1 decade ago

    1. -7y - 17 > 11

    -7y > 28

    y < -4

    A circle at -4, and an arrow to the left.

    2. 16 < 3x + 1 < 4

    15 < 3x < 3

    5 < x < 1

    This doesn't make sense.

    Maybe you meant 16 < 3x + 1 < 4?

    Then the solution is 5 > x > 1.

    The graph consists of open circles at 5 and 1, and a line segment connecting them.

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