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# Solve the Given Equation?

y^2 + 3 = y(4-y)

Please show how you get your answer. thank you.

### 1 Answer

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- NuzhahLv 51 decade agoFavorite Answer
y^2 + 3 = y(4-y)

y^2 +3=4y-y^2

y^2+y^2-4y+3=0

2y^2-4y+3=0

solve using quadradic formula

you will get

y=

4+sqrt -32

------------

4

=4+ sqrt 32i^2

-------------------

4

=4+4i sqrt2

----------------

4

=1+i sqrt 2

or

you will get

y=

4-sqrt -32

------------

4

=4- sqrt 32i^2

-------------------

4

=4-4i sqrt2

----------------

4

=1-i sqrt 2

ans=

y=1+isqrt2

y=1-isqrt2

note

sqrt -1=sqrt i^2

sqrt -32=sqrt 32i^2

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