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A PERMUTATION PROBLEM! HELP D:?
Petey is on the same round table as his brother, John and his sister, Jane. If they sit next to each other they will start fighting. If the seats for the table as chosen at random, find the probability that exacly 2 of the siblings are sitting together.
There are 12 seats at the circular table.
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- M3Lv 71 decade agoFavorite Answer
treating clockwise & anticlockwise as different
seat 2 siblings from 3 anywhere : 3P2 = 6 ways,
and treat them as the reference
the 3rd sibling can be seated in any of (10-2 adjoining) = 8 ways
the remaining 9 can be seated in 9P9 = 9! ways
stipulated seating arrangements = 6*8*9!
total seating arrangements = (12-1)!
probability = 6*8*9!/11!
= 6*8/(10*11)
= 24/55
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