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# Please answer my math problem.?

The length of a big rectangle is thrice the length of the small rectangle.If the 2 rectangles have the same width and the area of the big rectangle is 16cm^2,find the area of the small rectangle.

### 4 Answers

- 1 decade agoFavorite Answer
So if we use the variable "x" to represent the length of the small rectangle and "y" to represent the widths (which are equal), and since we know the area of a rectangle is length * width, then you can write two equations:

3x * y = 16 cm^2

x * y = A

Substitute the second equation into the first and you get:

3A = 16 cm^2

Solve for A.

- 1 decade ago
Here is an easy way of doing it

x * y = A (equation for small rectangle if x is length and y is width)

3x * y = 16 (equation for the big rectangle with thrice the length)

3(x*y) = 16 (since multiplication order doesn't matter)

x * y = 16/3 (divide by 3, now it looks like the first equation)

So A = 16/3 = 5.3333333..... cm^2

- ranjankarLv 71 decade ago
Let the dimensions of the small rectangle be l X b

Dimensions of the big rectangle = 3l X b

Area of big rectangle = 3l X b = 16

l X b = 16/3 = 5.33 cm = area of small rectangle ANSWER

- 1 decade ago
pretty sure its 5.3333333333333333333333333333333333333333333333333333333 recurring