Best AnswerAsker's Choice

So we first take a look at the givens:

x=6 when y=0 (since x-intercept is 6)

x=0 when y=4 (since y-intercept is 4)

Since we have two points of this line, we can find its slope.

We get a slope of (4-0)/(0-6) or -4/6.

Using the slope-intercept form:

y=(-4/6)x+4

We can turn this into standard form by moving all the terms to one side

(-4/6)x-y+4=0

-4x-6y+24=0

4x+6y-24=0

2x+3y-12=0

This equation in standard form is:

2x+3y-12=0

P.S.

The reason why your way doesn't work is because the slope-intercept form you're using has to use x and y coordinates from one specific point and you're using information from two different points. The y intercept is a different spot from the x intercept, so the way you're doing it won't give you an answer.

P.P.S. Why am I getting thumbed down? I did everything right. D:

I hope this helped! :)

x=6 when y=0 (since x-intercept is 6)

x=0 when y=4 (since y-intercept is 4)

Since we have two points of this line, we can find its slope.

We get a slope of (4-0)/(0-6) or -4/6.

Using the slope-intercept form:

y=(-4/6)x+4

We can turn this into standard form by moving all the terms to one side

(-4/6)x-y+4=0

-4x-6y+24=0

4x+6y-24=0

2x+3y-12=0

This equation in standard form is:

2x+3y-12=0

P.S.

The reason why your way doesn't work is because the slope-intercept form you're using has to use x and y coordinates from one specific point and you're using information from two different points. The y intercept is a different spot from the x intercept, so the way you're doing it won't give you an answer.

P.P.S. Why am I getting thumbed down? I did everything right. D:

I hope this helped! :)

### Other Answers (4)

Relevance-
If the line has x-intercept 6, then it passes through the point (6, 0).

The y-intercept is 4, so it passes through the point (0, 4).

From these two points, you can find the slope of the line.

Slope (m) = (y2 - y1) / (x2 - x1)

= (4 - 0) / (0 - 6)

= 4 / -6 = -4/ 6 = -2/3.

The y-intercept is 4, so c = 4.

The equation for a straight line is y = mx + c, where m is the slope, and c is the y-intercept.

So, the equation of this line is y = -2x/3 + 4.

I hope that helps. :)

ILoveMaths07. -
The slope is 4/6 or 2/3 and the y-intercept is 4.

So the equation in slope-intercept form is

y = (2/3)x + 4 Now, put it in standard form.

-(2/3)x + y = 4 Multiply by -3 to get

2x -3y = -12 -
So the line goes through (6,0) and (0,4)

The equation for the line is

y = mx + b

Where m is the slope and b is the y intercept;

Slope = (y2 - y1)/(x2 - x1)

Slope = (0 - 4)/(6 - 0)

Slope = -4/6

The slope is -2/3 and the y intercept is 4, so:

y = -2/3x + 4 -
2x+3y=12

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Find an equation in standard form for the line described?

Has x intercept 6 and y intercept 4

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