Find an equation in standard form for the line described?

Follow
  • Follow publicly
  • Follow privately
  • Unfollow
Has x intercept 6 and y intercept 4
Update : I don't want the answer, I want to know how to solve it. I get to y= ...show more
Best AnswerAsker's Choice
So we first take a look at the givens:
x=6 when y=0 (since x-intercept is 6)
x=0 when y=4 (since y-intercept is 4)

Since we have two points of this line, we can find its slope.
We get a slope of (4-0)/(0-6) or -4/6.

Using the slope-intercept form:
y=(-4/6)x+4

We can turn this into standard form by moving all the terms to one side
(-4/6)x-y+4=0
-4x-6y+24=0
4x+6y-24=0
2x+3y-12=0

This equation in standard form is:
2x+3y-12=0

P.S.
The reason why your way doesn't work is because the slope-intercept form you're using has to use x and y coordinates from one specific point and you're using information from two different points. The y intercept is a different spot from the x intercept, so the way you're doing it won't give you an answer.

P.P.S. Why am I getting thumbed down? I did everything right. D:

I hope this helped! :)

Asker's rating & comment

5 out of 5
You got thumbs down because standard for is Ax+By=C
The answer is actually 2x+3y=12.
hahahha but thank you :) This helped a lot.
  • 3
  • Comment

Other Answers (4)

Rated Highest
  • Rated Highest
  • Oldest
  • Newest
  • Unknown answered 4 years ago
    So the line goes through (6,0) and (0,4)

    The equation for the line is

    y = mx + b

    Where m is the slope and b is the y intercept;

    Slope = (y2 - y1)/(x2 - x1)
    Slope = (0 - 4)/(6 - 0)
    Slope = -4/6

    The slope is -2/3 and the y intercept is 4, so:

    y = -2/3x + 4
    • 1
    • Comment
  • Mclovin1022 answered 4 years ago
    2x+3y=12
    • 1
    • Comment
  • ILoveMaths07 answered 4 years ago
    If the line has x-intercept 6, then it passes through the point (6, 0).
    The y-intercept is 4, so it passes through the point (0, 4).

    From these two points, you can find the slope of the line.

    Slope (m) = (y2 - y1) / (x2 - x1)
    = (4 - 0) / (0 - 6)
    = 4 / -6 = -4/ 6 = -2/3.

    The y-intercept is 4, so c = 4.

    The equation for a straight line is y = mx + c, where m is the slope, and c is the y-intercept.

    So, the equation of this line is y = -2x/3 + 4.

    I hope that helps. :)

    ILoveMaths07.
    • Rate
    • Comment
  • pgd_malaka answered 4 years ago
    The slope is 4/6 or 2/3 and the y-intercept is 4.
    So the equation in slope-intercept form is
    y = (2/3)x + 4 Now, put it in standard form.

    -(2/3)x + y = 4 Multiply by -3 to get
    2x -3y = -12
    • Rate
    • Comment
  • Sign In 

    to add your answer

Who is following this question?

    %
    BEST ANSWERS
    Member Since:
    Points: Points: Level
    Total Answers:
    Points this week:
    Follow
     
    Unfollow
     
    Block
     
    Unblock