# Ca + Cl2 ---> CaCl2 percent yield?

can you show me how to find the answer to number one on the "percent yield" page?

Relevance

Ca + Cl2 → CaCl2

1.0mol of Ca and 1.00 mol of Cl2 were present as reactants.

Only 106 g of CaCl2 is produced.

What is the percent yield?

Ca + Cl2 → CaCl2

This balanced equation states that 1 mole of Ca will react with 1 mole of Cl2 to produce 1 mole of CaCl2.

1 mole of Ca = 40.1 grams

1 mole of Cl2 = 2 * 35.5 = 71.0 grams of Cl2

So, 40.1 + 71.0 = 111.1 grams of CaCl2 should have been produced!!

Since only 106 grams of CaCl2 was produced, the percent yield =

% yield = (106 ÷ 111.1) * 100 = 95.41%

Source(s): I am now retired and enjoy helping people understand math, chemistry, and physics. If you would like me to answer your questions in the future, request that I be one of your contacts. Then when you post a question, I will receive it via email. Otherwise I just search randomly for a question to answer. Thanks for the opportunity to be of help
• pls help me

In which of the following reactions do oxidation and reduction occur. (15 pts.)

a. 2CO + O2-------------------------2CO2

b. Mg + H2SO4---------------- H2 + MgSO4

c. CaCl2 + NaCO3--------------------CaCO3 + NaCl

d. H20 + SO2 --------------------H2SO3

e. H2 + S-----------------H2SO3