? asked in Science & MathematicsChemistry · 1 decade ago

Chem Solubility Question?

Solid Mg(OH)2, which has a solubility product constant of 1.5x10 -11, dissolves in water when NH4CL is added to the solution because,

1. MgCl2 is a salt and completely ionized in water solution.

2. OH- ion reacts with Cl- ion to form the weak acid HClO.

3. OH- ion is converted to NH4OH by reaction with NH4+

4. Mg+2 forms a very stable complex ion with ammonia.

5. One of the ions from Mg(OH)2 is oxidized to form a different species.

3 Answers

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  • Dr.A
    Lv 7
    1 decade ago
    Favorite Answer

    The equilibrium is :

    Mg(OH)2 (s) <=> Mg2+ (aq) + 2 OH- (aq)

    adding NH4+

    the reaction that occurs is

    OH- + NH4+ = NH4OH

    3 is the correct answer

  • linzey
    Lv 4
    4 years ago

    so which you will possibly your I.C.E. table you have an X of 0.5 moles via certainty 1X of A grew to become into used with 2X of B. so which you're arranged to have 2X of C which would be a million.0 moles. so which you have 0.5 moles A, 0.5 moles B and a million.0 moles C. Divide those values by ability of 0.250 L to locate their molarity. Then place into the ok expression. ok=(a million.0moles/0.250L)^2/((0.5moles/0.25... in spite of the fact that this answer comes out to ought to wish to be dazzling and the ok is unit-much less.

  • 4 years ago

    with the purpose on your I.C.E. table you have an X of 0.5 moles with the aid of actuality 1X of A grew to alter into into used with 2X of B. so which you're in a position to have 2X of C which may well be a million.0 moles. so which you have 0.5 moles A, 0.5 moles B and a million.0 moles C. Divide those values by using 0.250 L to discover their molarity. Then place into the ok expression. ok=(a million.0moles/0.250L)^2/((0.5moles/0.25... in spite of the shown fact that this answer comes out to could opt to be staggering and the ok is unit-much less.

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