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# Algebra I - Evaluating. I'm confused... Please help?

1. Evaluate 4!.

A) 4

B) 12

C) 24

2. Evaluate 0! + 1!.

A)0

B)1

C)2

3. Evaluate 5!/3!

A)20

B)60

C)120

4. Evaluate 7!/5! 2!

A)1

B)21

C)42

5. Evaluate P(3, 0).

A) 0

B) 1

C) 6

### 5 Answers

- PranilLv 71 decade agoFavorite Answer
1. Evaluate 4!.

= 4 × 3 × 2 × 1

= 24

C) 24

2. Evaluate 0! + 1!.

= 1 + 1 = 2

C)2

3. Evaluate 5!/3!

= 3! × 4 × 5/3!

= 20

A)20

4. Evaluate 7!/5! 2!

= 5! × 6 × 7/5! 2!

= 21

B)21

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- Anonymous1 decade ago
In other words, you don't know what a factorial is.

"4!" is pronounced "Four factorial", and it means 4*3*2*1. In general, n! is the product of all the integers from n down to 1.

0! however is a special case, and we define 0! as 1. There are reasons for this, which I won't go into right now. So 0! + 1! is 1+1. I'm sure you can take it from there!

There are also the "permutation" and "combination" functions:

P(n,k) = n! / (n-k)!

C(n,k) = n! / [ k! (n-k)! ]

You should be able to do all of the problems now.

- normanLv 71 decade ago
4! = 4*3*2*1 = 24 (c)

0! = 1

0!+1! = 2 (c)

5!/3! = 4 * 5 = 20 (a)

7!/5!2! = 6 * 7/2 = 21 (b)

p(3,0) = 1 (b)

- Amar SoniLv 71 decade ago
. Evaluate 4!.= 4x3x2x1 =24

A) 4

B) 12

C) 24...........................................Ans

2. Evaluate 0! + 1!.=1+1=2

A)0

B)1

C)2............................................Ans

3. Evaluate 5!/3!= (5x4x3x2x1)/(1x2x3) =5x4=20

A)20.............................................ans

B)60

C)120

4. Evaluate 7!/5! 2! = (7x6x5x4x3x2x1)/(1x2x3x4x5)(1x2) =7x6/2=21

A)1

B)21.......................................Ans

C)42

5. Evaluate P(3, 0).= 3P0= 1

A) 0

B) 1...............................Ans

C) 6

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