Math problem help? rational abs. value inequality?

|x+7/x-3| > or equal to 2

so that's the absolute value of (x+7 divided by x-3) is greater than or equal to 2

Update:

jesus christ your wrong too.

5 Answers

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  • 10 years ago

    Use the identity |a / b| = |a| / |b|

    |x+7/x-3| ≥ 2

    |x+7| / |x-3| ≥ 2

    |x+7| ≥ 2 |x-3|

    x+7 ≥ ±2 (x-3)

    x+7 ≥ 2(x-3) = 2x - 6

    -x ≥ -13

    x ≤ 13

    and

    x+7 ≥ -2(x-3) = -2x + 6

    3x ≥ -1

    x ≥ -1/3

    x doesn't equal 3 because this would give division by zero in the original inequality.

    x = [-1/3, 3) U (3, 13]

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  • 10 years ago

    let me denote greater than equal to by >=

    now when x+7 / x-3 >0

    then | x+7 / x-3| = x+7 / x-3

    so x+7 / x-3>=2

    =>x+7>=2x-6

    =>7+6>=2x-x=x

    =>x<=13 [ <= means less than or equal to]

    when x+7 / x-3 <0

    | x+7 / x-3| = -( x+7 / x-3)

    so -( x+7 / x-3)>=2

    => -x-7.>=2x-6

    => 6-7>=2x+x=3x

    =>-1>=3x

    =>3x<=-1

    =>x<= -1/3

    thus we get x<= -1/3

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  • Faz
    Lv 7
    10 years ago

    Case 1:

    (x+7) / (x-3) >= 2

    Multiply both sides by (x-3)² to preserve sign of inequality, so

    (x+7)(x-3) >= 2(x-3)²

    -(x-13)(x-3) >= 0

    x-intercepts at 3 and 13. Parabola opens down, so

    3 < x <= 13

    Case 2:

    (x+7) / (x-3) <= -2

    (x+7)(x-3) <= -2(x-3)²

    (x-3) (3x+1) <= 0

    x-intercepts at x=3, x=-1/3. Parabola opens up, so:

    -1/3 <= x < 3

    So our two conditions are

    -1/3 <= x < 3

    3 < x <= 13

    Note that x=3, is a vertical asymptote.

    Combining these conditions, inequality holds when:

    [-1/3, 3) U (3, 13]

    Here's a plot to confirm:

    http://www.wolframalpha.com/input/?i=Plot[Abs[%28x...

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  • 3 years ago

    |(x+7)/(x-3)| ? 2 this suggests: (x+7)/(x-3) ? 2, or -((x+7)/(x-3)) ? 2. case a million: (x+7)/(x-3) ? 2 Multiply the two factors by technique of x-3, giving x+7 ? 2(x-3), or x+7 ? 2x - 6. Subtract x from the two factors and upload 6 to the two factors, giving 13 ? x, or x ? 13. case 2: -((x+7)/(x-3)) ? 2 Multiply the two factors by technique of -a million, giving (x+7)/(x-3) ? -2. Multiply the two factors by technique of x-3, giving x+7 ? -2(x-3), or x+7 ? -2x + 6. upload 2x to the two factors and subtract 7 from the two factors, giving 3x ? -a million. sparkling up for x: x ? -a million/3.

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  • 10 years ago

    I'm gonna use >_ as greater than or equal to.

    (x+7) / (x+3) >_ 2

    x + 7 >_ 2x +6

    7>_x+6

    1>_x

    x_< 1

    Soooo I got x is smaller than or equal to 1...

    Hope I helped.

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