Alice asked in Science & MathematicsPhysics · 10 years ago

The Hubble Space Telescope orbits Earth 615 km above Earth's surface.?

The Hubble Space Telescope orbits Earth 615 km above Earth's surface. What is the period of the telescope's orbit?

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  • DH
    Lv 7
    10 years ago
    Best Answer

    From Newton's Laws we have

    GMm/r^2 = m*v^2/r but v = 2πr/T

    So GM/r^2 = 4π^2r/T^2

    So T = sqrt(4π^2*r^3/GM) = sqrt(4π^2*(6.38x10^6 + 615x10^3)^3/(6.67x10^-11*5.98x10^24)

    = 5820s = 1.62 hr

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