# Consider the circuit shown in the figure below, in which V = 3 V and R = 11 . Find and tabulate the current th?

Consider the circuit shown in the figure below, in which V = 3 V and R = 11ohm . Find and tabulate the current through and the potential difference across each resistor.

resistor current (A) potential difference (V)

3 ohm

R (11ohm )

48 ohm

16 ohm

Update:

Relevance

The R, 16, & 48 are parallel so 1/Req = 1/11 + 1/16 + 1/48 = 0.1742

So R = 1/0.1742 = 5.74Ω

This is in series with the 3 giving Req = 8.74Ω

So the current through the 3Ω = V/R = 3/8.74 = 0.343A

and V (3) = 0.343*3 = 1.03V

Now voltage over the parallel combination = i*Req = 0.343A*5.74Ω = 1.97V

Since they are in parallel V over each of the the three other R's is 1.97V

So I(11Ω) = V/R = 1.97/11 = 0.179A

and I(48Ω) = V/R = 1.97/48 = 0.0410 A

and I(16Ω) = V/R = 1.97/16 = 0.123A

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• In the previous question, what would happen if you were to reduce the resistance of the resistor labeled R? (Select all that apply.)

The battery's voltage would decrease

The current through the 48 Ohm resistor would decrease

The voltage drop across the 48 Ohm resistor would increase

There would be more current through the 3 Ohm resistor

The battery's voltage would increase

The voltage drop across the 16 Ohm resistor would decrease

The battery would put out more current

The battery would put out less current

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