? asked in Science & MathematicsPhysics · 1 decade ago

Consider the circuit shown in the figure below, in which V = 3 V and R = 11 . Find and tabulate the current th?

Consider the circuit shown in the figure below, in which V = 3 V and R = 11ohm . Find and tabulate the current through and the potential difference across each resistor.

resistor current (A) potential difference (V)

3 ohm

R (11ohm )

48 ohm

16 ohm

2 Answers

Relevance
  • DH
    Lv 7
    1 decade ago
    Favorite Answer

    The R, 16, & 48 are parallel so 1/Req = 1/11 + 1/16 + 1/48 = 0.1742

    So R = 1/0.1742 = 5.74Ω

    This is in series with the 3 giving Req = 8.74Ω

    So the current through the 3Ω = V/R = 3/8.74 = 0.343A

    and V (3) = 0.343*3 = 1.03V

    Now voltage over the parallel combination = i*Req = 0.343A*5.74Ω = 1.97V

    Since they are in parallel V over each of the the three other R's is 1.97V

    So I(11Ω) = V/R = 1.97/11 = 0.179A

    and I(48Ω) = V/R = 1.97/48 = 0.0410 A

    and I(16Ω) = V/R = 1.97/16 = 0.123A

    • Commenter avatarLogin to reply the answers
  • 5 years ago

    In the previous question, what would happen if you were to reduce the resistance of the resistor labeled R? (Select all that apply.)

    The battery's voltage would decrease

    The current through the 48 Ohm resistor would decrease

    The voltage drop across the 48 Ohm resistor would increase

    There would be more current through the 3 Ohm resistor

    The battery's voltage would increase

    The voltage drop across the 16 Ohm resistor would decrease

    The battery would put out more current

    The battery would put out less current

    • Commenter avatarLogin to reply the answers
Still have questions? Get your answers by asking now.