# Boyle's Law Problems..?

I need help on some questions for chemistry please.

1.A sample of 100.0 mL of oxygen has a pressure of 10.50 kPa. The pressure is then changed to 9.91 kPa. Assume that temperature remains constant,

a.predict whether the volume will increase or decrease.

b.What is the new volume of the gas?

2.A flask containing 95.0cm^3 of hydrogen was collected at a presure of 731 mm of mercury. At what pressure would the volume of hydrogen be 70.0cm^3? Assume that temperature reamins constant.

a.Predict whether the pressure will increase or decrease.

b.What is the pressure of the gas at 70cm^3?

3.A gas a volume pf 50.0m^3. Assuming that temperature remains constant, what volume would the gas occupy

a.if the pressure is doubled?

b.if the pressure is cut in half?

c.if the pressure is tripled?

4.A scuba diver inflates a balloon to 0.25ft^3 at a depth of 99ft (where the pressure is about 4 atm) Assume that temperature remains constant.

a.in its ascent, will the balloon increase or decrease in volume?

b.what will the volume of the balloon be at the surface (1.0 atm)?

volume=?

5.A gas is confined in a cylinder with a movable piston at one end. When the volume of the cylinder is 760.0 cm^3, the pressure of the gas is 125.0 kPa. When the cylinder volume is reduced to 450.0cm^3, what is the pressure in kPa? Assume that temperature remains constant.

Relevance
• Dr.A
Lv 7

Boyle's law : p1V1 = p2V2

1

the pressure decreases and the volume will increase

100.0 x 10.50 = V x 9.91

V = 106.0 mL

2

the volume decreases and the pressure will increase

95.0 x 731 = 70.0 x p

p = 992 mm Hg

3

let initial pressure = p

a

50.0 p = V x 2p

V = 50.0 p / 2p = 50.0 /2 = 25.0 m^3

b

50.0 p = V x p/2

100 p = V x p

V = 100 m^3

c

50.0 p = V x 3p

V = 50.0 p / 3p = 50.0 /3 =16.7 m^3

4

in its ascent the pressure decreases and the volume will increase

0.25 x 4 = V x 1.0

V = 1.0 ft^3

5

760.0 x 125.0 = 450 p

p = 211.1 kPa

• Anonymous

1. given

Volume 1= 100.0 mL

pressure 1= 10.50kPa

Pressure 2= 9.91kPa

required:

Volume 2

using boyles law formula P1V1 = P2V2

we can aquire the new volume of gas using the new formula and by answering you can say wheter the volume increases or decreases

V2= (P2)(V1)/(P1)

2. volume1 = 95.0 cm^3

Pressure1 = 731 mmHg

Volume 2= 70.0 cm^3

required

pressure 2

again. P1V1 = P2V2

P2= (P1)(V2)/(V1)

subtitute the values and you can get the answer from your questions