What volume (in mLs) of 0.100 M sodium hydroxide solution must be added to 20.0 mL of 0.13 M sulfuric acid ..?

Hi! just wondering, What volume (in mLs) of 0.100 M sodium hydroxide solution must be added to 20.0 mL of 0.13 M sulfuric acid solution to reach the end point?

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  • Dr.A
    Lv 7
    10 years ago
    Favorite Answer

    moles H2SO4 = 0.0200 L x 0.13 M=0.0026

    the balanced equation is

    H2SO4 + 2 NaOH = Na2SO4 + 2 H2O

    the ratio between H2SO4 and NaOH is 1 : 2

    moles NaOH required = 2 x 0.0026 =0.0052

    Volume of NaOH = 0.0052/ 0.100 M = 0.052 L = 52.0 mL

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