## Trending News

# Quick maths question?

Help! Please help me answer this maths question?

http://i774.photobucket.com/albums/yy28/anthanhngu...

I tried to do it but I dont think I did it right

Thank you very much

### 1 Answer

- 1 decade agoFavorite Answer
Ok so here's what I'm thinking...

(i)

2 x <ABP = <MBA (defn of bisect)

2 x <BAP = <BAK (defn of bisect)

<MBA + <BAK = 180 (co int <s)

2 x <ABP + 2 x <BAP = 180 (substitution)

<ABP + <BAP = 90 (divided through by 2)

Also,

<ABP + <BAP + <BPA = 180 (sum of triangle)

( 90 ) + <BPA = 180 (substitution)

<BPA = 180 (proved)

(ii)

<ABP = <MBP (definition of bisect)

BP common

<BPA + <BPM = 180 (sum of straight line)

( 90 ) + <BPM = 180 (substitution)

<BPM = 90 = <BPA

Therefore triangle ABP is congruent to triangle BMP (two angles equal, side included)

Therefore AB = BM (corresponding parts of congruent triangles equal)

Hope this helps

Source(s): Been through high school On my way to be a maths teacher