Quick maths question?
Help! Please help me answer this maths question?
I tried to do it but I dont think I did it right
Thank you very much
- 1 decade agoFavorite Answer
Ok so here's what I'm thinking...
2 x <ABP = <MBA (defn of bisect)
2 x <BAP = <BAK (defn of bisect)
<MBA + <BAK = 180 (co int <s)
2 x <ABP + 2 x <BAP = 180 (substitution)
<ABP + <BAP = 90 (divided through by 2)
<ABP + <BAP + <BPA = 180 (sum of triangle)
( 90 ) + <BPA = 180 (substitution)
<BPA = 180 (proved)
<ABP = <MBP (definition of bisect)
<BPA + <BPM = 180 (sum of straight line)
( 90 ) + <BPM = 180 (substitution)
<BPM = 90 = <BPA
Therefore triangle ABP is congruent to triangle BMP (two angles equal, side included)
Therefore AB = BM (corresponding parts of congruent triangles equal)
Hope this helpsSource(s): Been through high school On my way to be a maths teacher