Romeo
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Romeo asked in Science & MathematicsMathematics · 1 decade ago

Quick maths question?

Help! Please help me answer this maths question?

http://i774.photobucket.com/albums/yy28/anthanhngu...

I tried to do it but I dont think I did it right

Thank you very much

1 Answer

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  • 1 decade ago
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    Ok so here's what I'm thinking...

    (i)

    2 x <ABP = <MBA (defn of bisect)

    2 x <BAP = <BAK (defn of bisect)

    <MBA + <BAK = 180 (co int <s)

    2 x <ABP + 2 x <BAP = 180 (substitution)

    <ABP + <BAP = 90 (divided through by 2)

    Also,

    <ABP + <BAP + <BPA = 180 (sum of triangle)

    ( 90 ) + <BPA = 180 (substitution)

    <BPA = 180 (proved)

    (ii)

    <ABP = <MBP (definition of bisect)

    BP common

    <BPA + <BPM = 180 (sum of straight line)

    ( 90 ) + <BPM = 180 (substitution)

    <BPM = 90 = <BPA

    Therefore triangle ABP is congruent to triangle BMP (two angles equal, side included)

    Therefore AB = BM (corresponding parts of congruent triangles equal)

    Hope this helps

    Source(s): Been through high school On my way to be a maths teacher
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