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# What is the derivative of sin squared plus cos squared x?

Derivative of sin^2(x)+cos^2(x)

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there is an identity in math that states that sin^2(x)+cos^2(x) = 1

so what you are trying to find is the derivative of 1

the derivative of any constant, -1, 1, 2, 30, 5839, any number, is 0

therefore, the derivative is 0

• sin^2(x) + cos^2(x) = 1

so d/dx ( sin^2(x) + cos^2(x) ) = d/dx (1) = 0

• sin^2+cos^2=1

sin=opp/hyp

cos=adj/hyp

so the equation=opp^2/hyp^2 +adj^2/hyp^2

=(opp^2+adj^2)/hyp^2

=hyp^2/hyp^2 (in a right triangle a^2+b^2=c^2 so opp^2+adj^2=hyp^2)

=1

therefore sin^2(x)+cos^2(x)=1

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