What is the magnitude of its average angular acceleration in rad/s^2 of the wheel?

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A flywheel rotating at 12 rev/s is brought to rest in 6 s.
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  • akm69 answered 4 years ago
By:-
omega(final) = omega(initial) + alfa x time
=>0 = 12 + alfa x 6
=>alfa = -12/6 = -2 rad/sec^2 [-ve showing that, it is retardation which is acting against the angular velocity (omega) to stop the wheel.]
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  • Quicksilver answered 4 years ago
    Simply
    α = ω/t (ω----->angular velocity α------->angular acceleration)
    α = 12x2π/6
    = 4π rad/sec^2
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  • stephen answered 4 years ago
    ave angular acceleration = change in angular velocity / change in time
    = -12rev/s / 6s
    = -2rev/s^2
    but you need to convert it to rad/s^2:
    1rev = 2pi rad
    -2rev/s^2 * 2pi rad/1rev = -4pi rad/s^2
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