# Two cars start moving from the same point. One travels south at 48 mi/h and the other travels west at 20 mi/h.?

At what rate is the distance between the cars increasing three hours later?

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interesting:

**distance from starting point car 1= c1

distance= speed x time

c1 = speed x time

c1= 48t

**distance form starting point car2=c2:

c2=20t

to calculate the distance between c1 and c2 use pythagoras

.........|

.........|

_____|______c2

.........|......../

.........|....../..d12

.........|c1/

.........|./

let be d12 =distance between c1 and c2 :

using pithagoras

(d12)^2 = (c1)^2 + (c2)^2

d12 = sqr [c1^2 + c2^2]

d12 =sqr(48^2t^2+20^2t^2)

d12 =sqr(2304t^2 + 400t^2)

d12 = sqr(2704t^2)

d12 =t*sqr(2704)

d12 =52t

the distance between the cars is increasing at a rate of 52 miles per hour

.

after 3 hours the distance between them is :

52*3 = 156 miles

I hope you understood

good luck

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• it would be 84

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• 1.35miles per hour/

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