Barlow
Lv 6
Barlow asked in Science & MathematicsMathematics · 10 years ago

Simplify (r^2-36)/((r+6)^2 ) by removing factors of 1…?

Simplify by removing factors of 1:

(r^2-36)/((r+6)^2 )

5 Answers

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  • a
    Lv 4
    10 years ago
    Best Answer

    (r^(2)-36)/((r+6)^(2))

    The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).

    ((r-6)(r+6))/((r+6)^(2))

    Reduce the expression by canceling out the common factor of (r+6) from the numerator and denominator.

    ((r-6)<X>(r+6)<x>)/((r+6)^(<X>2<x>))

    Reduce the expression by canceling out the common factor of (r+6) from the numerator and denominator.

    (r-6)/(r+6)

  • George
    Lv 7
    10 years ago

    (r^2 - 36) / (r + 6)^2.

    (r + 6)(r - 6) / (r + 6)(r + 6). One (r + 6) in the numerator and denominator cancel each other out.

    Answer: (r - 6) / (r + 6)

    Source(s): Self
  • 10 years ago

    (r^2 - 36) / (r + 6)^2

    =(r + 6) (r - 6) / (r + 6) (r+6)

    = (r - 6) / (r + 6)

  • 10 years ago

    (r-6)(r+6)/(r+6)(r+6)=(r-6)/(r+6)

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  • ?
    Lv 4
    3 years ago

    on the grounds that n^2-a million = (n+a million)(n-a million) and you will write (n+a million)^2 as (n+a million)(n+a million) you may rewrite your fraction as: (n+a million)(n-a million) ---------------- (n+a million)(n+a million) on the grounds that we multiply fraction for the time of it somewhat is written as: (n+a million)/(n+a million) X (n-a million)/(n+a million) on the grounds that (n+a million)/(n+a million) = a million you have: (n-a million) -------- X a million (n+a million) or (n-a million)/(n+a million) subsequently you have simplified by using removing aspects of a million.

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