Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. **There will be no changes to other Yahoo properties or services, or your Yahoo account.** You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

## Trending News

# Calculate the volume that each of the following samples of gas would occupy at STP?

0.25moles 0.5 moles 1 mole 2.5 moles

i dont understand this can you please help me?? thanks XD

0.25 moles o2 0.5 moles H2 1 mole N2 2.5 moles CO2

### 4 Answers

- 1 decade agoFavorite Answer
at STP, 1 mole of gas= 22.4 liters

use dimensional analysis.

..................22.4 liters

.25moles x -------------- = 5.6 liters

...................1 mole

.25 moles = 5.6 liters

.5 moles = 11.2 liters

1 mole = 22.4 liters

2.5 moles =56 liters

- Anonymous1 decade ago
The answers are:

(1) 5.68 L

(2) 11.4 L

(3) 22.7 L

(4) 56.8 L

However, to actually find these values for yourself, you'll use the Ideal Gas Law, then solve it for Volume before you actually start putting in values.

Law: PV = nRT. Solve.

V = nRT/P

This means --

V = Volume in liters

n = Number of moles

R = Universal Gas Constant [ 0.0820574587 L-atm/ (K-mol) ]

T = Temperature in Kelvin (273.15 K)

P = Pressure in atmospheres (0.986 atm)

T & P given above are from current IUPAC standard STP.

Situation (1)

n = 0.25 mol

V = nRT/P

V = { (0.25 mol) * [ 0.0820574587 L-atm/ (K-mol) ] * (273.15 K) } / (0.986 atm)

V = { ( 5.603 L-atm ) / (0.986 atm) }

V = 5.68 L

Situation (2)

n = 0.5 mol

V = nRT/P

V = { (0.5 mol) * [ 0.0820574587 L-atm/ (K-mol) ] * (273.15 K) } / (0.986 atm)

V = { (11.21 L-tm) / (0.986 atm) }

V = 11.4 L

Situation (3)

n = 1.0 mol

V = nRT/P

V = { (1.0 mol) * [ 0.0820574587 L-atm/ (K-mol) ] * (273.15 K) } / (0.986 atm)

V = { (22.41 L-atm) / (0.986 atm) }

V = 22.7 L

Situation (4)

n = 2.5 mol

V = nRT/P

V = { (2.5 mol) * [ 0.0820574587 L-atm/ (K-mol) ] * (273.15 K) } / (0.986 atm)

V = { (56.035 L-atm) / (0.986 atm) }

V = 56.8 L

Source(s): Geologist. http://hyperphysics.phy-astr.gsu.edu/HBASE/kinetic... http://en.wikipedia.org/wiki/Standard_conditions_f... - ?Lv 44 years ago
If the compound is certainly CCl4 (with lowercase 'L' ), the IUPAC call for this organic and organic compound is "tetrachloromethane". yet in addition bear in mind that this compound is "regularly" talked approximately as as "carbon tetrachloride". So until now you enter your answer be certain if the question is soliciting for the same old "IUPAC call" (IUPAC nomenclature is the same old naming convention in chemistry) or in basic terms the "project-loose" call.

- 1 decade ago
this is a chemistry question

first what gases are they we nees to know if it if oxygen nitrigen or any other gass