Perpendicular to y= 8x - 1, through (4,10)?
how do i show work?
- 10 years agoBest Answer
Well, A line that is perpendicular to: y = 8x - 1. Passes to (4,10).
To do this problem, you must know the purpose of Slope-intercept form, and what information of the line can be drawn from the format.
Y = MX + B
Y is the Y value, M is the Slope, X is the X value, + or - B is the Y-intercept.
If you did not know yet, the slope of line comparison to the slope of the line it is perpendicular to is a negative reciprocal. For example,
Slope of one line: 4.
Therfore, the slope of the perpendicular line is...
4m = -1 ( -1 represents the negative reciprocal ).
x = -1/4
The slope of the perpendicular line is -1/4.
Back to the original problem, the slope for this particular equation is 8.
Therefore, similarly, the slope of the line perpendicular to it is.. ( the negative reciprocal ).
8x = -1
x = -1/8
Now substitute the slope into the Y = MX + B format.
y = (-1/8)x + b
Substitute the given points to find the value of "B."
10 = (-1/8)4 + b
10 = -1/2 + b
b = 10 + 1/2
b = 10.5
Therefore, substitute the value of b back into the equation.
y = (-1/8)x + 10.5 is your answer.