the value of k and the velocity of the particle when x=-2m?

the acceleration of a particle is defined by the relation a=k(1-e^-x), where k is a constant. knowing that the velocity of the particle is v=9m/s when x=-3m and that the particle comes to rest at the origin, determine

Relevance

a = k(1-e^-x)

Since acceleration is the derivative of velocity, therefore we can write it as

dV/dt = k(1-e^-x)

dV = k(1-e^-x)dt

integral dV = integral [k(1-e^-x)]dt

V = k ( x - (-x) e^-x)

V = k x (1 + e^-x)

when x = -3, v = 9. Put the respective values in above equation.

9 = k (-3) ( 1 + e^-3)

k = -3 / (1 + e^-3)

Solving it, we get

k = -2.8577223806977896287661130596212