Anonymous

# Let R have probability mass function (pmf) p(r) = 1/8 for r = 1, 2, . . . , 8.?

Then I have to:

find the cumulative distribution function (cdf) of R

What does this also mean!

Thanks for any help.. I have tried the internet, but it is all too complicated.

Relevance

R may take the values form 1 to 8 with equal probability of 1/8:

P(R = 1) = 1/8

P(R = 2) = 1/8

P(R = 3) = 1/8

P(R = 4) = 1/8

P(R = 5) = 1/8

P(R = 6) = 1/8

P(R = 7) = 1/8

P(R = 8) = 1/8

R cannot take any other values

The cdf of R is P(R <= t) and is often written F(R)

Here F(R) = 0 for t < 1

F(R) = t/8 for 1 <= t <= 8

F(R) = 1 for t > 8

Note how F(R) must be defined for all values of t.

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