1)

In the diagram: GO TO http://castlelearning.com/review/Courses/geometry/... for diagram

line RL perpendicular to line LP and M is the midpoint of line TP . Which statement could be used to prove ΔTMR ≅ ΔPML?

1. SAS ≅ SAS

2. AAS ≅ AAS

3. HL ≅ HL

4. SSS ≅ SSS

2)

In the diagram, Click http://castlelearning.com/review/Courses/geometry/... TO SEE DIAGRAM

Line PR ≅ line SQ,line PR ⊥ line RQ, and line SQ ⊥ line RQ . Which statement can be used to prove that ΔPQR ≅ ΔSRQ?

1. AAS ≅ AAS

2. SAS ≅ SAS

3. HL ≅ HL

4. SSS ≅ SSS

3)

In the accompanying diagram GO 2 http://castlelearning.com/review/Courses/geometry/...

TO SEE DIAGRAM

Given:

THE diagram of parallelogram ABCD, Line DE ≅ line BF .

Triangle EGC can be proved congruent to triangle FGA by

1. HL ≅ HL

2. AAA ≅ AAA

3. AAS ≅ AAS

4. SSA ≅ SSA

4)

In the accompanying diagram, GO 2 http://castlelearning.com/review/Courses/geometry/...

Line AB and line CD intersect at E.

If m∠AEC = 4x - 40 and m∠BED = x + 50, find the number of degrees in m∠AEC.

WHAT DOES m∠AEC = __________?

If you have time please give explanations!!!

Relevance

1. AAS because

the right angle

the vertical angle in the middle

and then the midpoint creating 2 congruent lines

2. SAS because

PR is congruent to SQ

the right angles

both share RQ

3. AASbecause

EC would be congruent to AF

vertical angles

<ECG woud be congruent to <FAG

4. m <AEC would be 80 degrees

becuase <AEC is congruent to <BED since they are vertical angles and you would put them equal to each other

4x - 40 = x + 50

3x - 40 = 50

3x = 90

x = 30

then you plug in 30 in the equation for <AEC

<AEC = 4 (30) - 40

120 - 40

<AEC = 80 degrees

HOPE THIS HELPS!!!!

Source(s): did this about 3 weeks ago in GEOMETRY class
• SPB
Lv 6

1. AAS

2. SAS

3. AAA

4. 80

opposite angles are congruent so

4x - 40 = x + 50

4x = x + 90

3x = 90

x = 30

4x-40

120 - 40 = 80

It's been a long time...check my answers