求各成分的重量百分比。

Mixture的各成分如下:

Stearic acid:2.5 g

Anhydrated Lanolin:0.75 g

Mineral Oil:2.5 ml

Triethanolamine:0.5 ml

Water:12ml

求各成分的重量百分比是多少?

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    版主你好

    1ml (毫升) = 1c.c = 1g(克)

    所以總重量是:2.5+0.75+2.5+0.5+12=18.25g

    所以...

    Stearic acid:2.5 g.................2.5/18.25=0.137=13.7%

    Anhydrated Lanolin:0.75 g.....0.75/18.25=0.041=4.1%

    Mineral Oil:2.5 ml.................2.5/18.25=0.137=13.7%

    Triethanolamine:0.5 ml..........0.5/18.25=0.274=2.74%

    Water:12ml..........................12/18.25=0.6575=65.75%

    合計:13.7+4.1+13.7+2.74+65.75=約100%

    2009-12-29 10:49:07 補充:

    對不起,

    回答時是將Mineral Oil與Triethanolamine視為與水一樣的比重計算的,如果這兩樣東西的比重不同於水,那就要再計算出它的真正重量,重新計算之。

    換言之,Mineral Oil:2.5 ml不一定是等於2.5g

    Triethanolamine:0.5 ml也不一定是等於0.5g

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