Question about continuity?
A water line with an itnernal radius of a 6.5e-3 m is connect to a shower heard that has 12 holes. The speed of the water in the line is 1.2 m/s.
a. what is the volume flow rate in the line?
b. at what speed does the water leave one of the holes (hole radius of 4.6e-4 m) in the head?
Please explain step by step. >.<
I really do fail at physics. *sigh*
I iwll choose best answer
Thank you so much for taking the time to aid my stupidity.
- SteveLv 71 decade agoFavorite Answer
a) Vfr = v*A = 1.2*π*(.0065²) = 1.6E-4 m^3/sec
b) Since there are 12 holes, the total head area Ah = 12*π*.00046² = 7.977E-6 m^2. The pipe area Ap = π*.0065² = 1.327E-4 m^2.
Vh = Vp*Ap/Ah = 1.2*1.327E-4/7.977E-6 = 19.96 m/s