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# 10 points for best answer. Math help. How do you solve this?

So I want to know how to do this. Can you explain what I need to do?:

Here is the question: Write a polynomial function in standard form with the following zeroes. 2,3,4

Thanks in advance!

### 4 Answers

- Anonymous1 decade agoFavorite Answer
✐Explanation✐

Work backward!

Zeroes = 2, 3, 4

(x - 2)(x - 3)(x - 4) = 0

Factor.

(x² - 5x + 6)(x - 4) = 0

x³ - 4x² - 5x² + 20x + 6x - 24 = 0

x³ - 9x² + 26x - 24 = 0

Source(s): Knowledge - Ashley JeanneLv 51 decade ago
Pretty simple. It's the reverse of a factoring problem.

If the zeroes are 2, 3, 4, then the factors are (x - 2)(x - 3)(x - 4). Now multiply them out.

(x^2 - 5x + 6)(x - 4) =

x^3 - 5x^2 +6x - 4x^2 + 20x - 24 =

x^3 -9x^2 + 26x - 24

All done

Source(s): My Cranium Branium - workoutgirl1235Lv 61 decade ago
If 'a' is a zero, or root, then x - a is a factor.

We will assume that there is no monomial factor here.

(x - 2)(x - 3)(x - 4) = 0

(x - 2)(xÂ² - 7x + 12) = 0

xÂ³ - 7xÂ² + 12x - 2xÂ² + 14x - 24 = 0

xÂ³ - 9xÂ² + 26x - 24 = 0

- Anonymous1 decade ago
If r is a root then x-r is a factor. So the factors of your polynomial are (x-2)(x-3)(x-4). Multiply these together and you will get a x^3 polynomial with your given roots.

have a nice night.