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Physics geniuses, please help?
A car tire is 59.0 cm in diameter. The car is traveling at a speed of 19.0 m/s .
a. What is the tire's rotation frequency, in rpm?
b. What is the speed of a point at the top edge of the tire?
c. What is the speed of a point at the bottom edge of the tire?
- Anonymous1 decade agoFavorite Answer
a. 19/0.59pi = 10.25 rp - second = 615 rpm.
b. Because of c, we know the tire moves fast enough to cancel out the traveling speed of the car completely. Therefore, the speed at the top is twice the speed of the car: 38.0 m/s
c. The tire hits the ground there, so the speed is 0 m/s: the rubber doesn't more relative to the ground.