R asked in Science & MathematicsMathematics · 1 decade ago

if v varies jointly as h and the square of b: and v is 288 when h=6 and b =12, find v when h=3 and b =10?

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  • 1 decade ago
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    v ∝ hb²

    v = khb², where k = constant of proportionality

    288 = k(6)(12)²

    k = (1/3)

    So, v = (1/3)hb²

    Now, when h = 3 and b = 10,

    v = (1/3)(3)(10)² = 100

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