# if v varies jointly as h and the square of b: and v is 288 when h=6 and b =12, find v when h=3 and b =10?

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- anonymous89Lv 71 decade agoFavorite Answer
v ∝ hb²

v = khb², where k = constant of proportionality

288 = k(6)(12)²

k = (1/3)

So, v = (1/3)hb²

Now, when h = 3 and b = 10,

v = (1/3)(3)(10)² = 100

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