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# find the derivative of h(x) = (ln(x)^cos(2x)?

Im not sure of this question

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- mohanrao dLv 71 decade agoFavorite Answer
let h(x) = y = ln (x)^ cos(2x)

taking logs

ln y = cos(2x) ln ln(x)

differentiating

y ' / y = cos(2x) (1 / ln x)(1/x) + ln ln(x) { -2 sin(2x) }

y ' / y = cos(2x) (1 /x ln x) - 2 sin(2x) ln ln(x)

y ' = ln (x)^ cos(2x) [ cos(2x) (1 /x ln x) - 2 sin(2x) ln ln(x) ]

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