Best Answer

You can use the dot product.

First find the magnitude of A and B

|A| = sqrt (4^2 + 5^2) = 6.40

|B| = sqrt (2^2 + 3^2) = 3.61

Now find the | A xB| = |-8 +15| = 7

cos y = |Ax B|/ |A||B| = 7/23.1 = 0.303

y = 72.4 degrees, this is the angle between the vectors

First find the magnitude of A and B

|A| = sqrt (4^2 + 5^2) = 6.40

|B| = sqrt (2^2 + 3^2) = 3.61

Now find the | A xB| = |-8 +15| = 7

cos y = |Ax B|/ |A||B| = 7/23.1 = 0.303

y = 72.4 degrees, this is the angle between the vectors

How do you compute the angle between two vectors?

Compute the angle, in radians, between the two vectors:

A = -4i^ + 5j^

B = 2i^ + 3j^

Just for clarification, the ^ should be ABOVE the i or j, but I can't get it to come out correctly.

Thanks!

A = -4i^ + 5j^

B = 2i^ + 3j^

Just for clarification, the ^ should be ABOVE the i or j, but I can't get it to come out correctly.

Thanks!

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