# How do you solve for x with the given equation?

(6.4)^1/2 = x (2-x)^-1
I drew a blank on this problem and I need a little help. I resorted to my calculator and graphed the equation. I found the zero of the equation, and found it out to be ~ 1.43.
I was able to bring the equation down to:
x + x(6.4^(1/2)) - 2(6.4^(1/2))
I cannot remember how to factor...
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(6.4)^1/2 = x (2-x)^-1

I drew a blank on this problem and I need a little help. I resorted to my calculator and graphed the equation. I found the zero of the equation, and found it out to be ~ 1.43.

I was able to bring the equation down to:

x + x(6.4^(1/2)) - 2(6.4^(1/2))

I cannot remember how to factor the square root problems. It's been a while...

I gave you the right answer, so can you show me the steps please?

I drew a blank on this problem and I need a little help. I resorted to my calculator and graphed the equation. I found the zero of the equation, and found it out to be ~ 1.43.

I was able to bring the equation down to:

x + x(6.4^(1/2)) - 2(6.4^(1/2))

I cannot remember how to factor the square root problems. It's been a while...

I gave you the right answer, so can you show me the steps please?

Update:
Oh, duh! For some reason I was thinking that the square root was a power less than the lone x. That makes sense. Thanks very much!

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