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position and movement
A car undergoes uniform decleration along a straight road,Its velocity decreases from 30ms^-1 after travelling a distance of 100m.How much further will the car travel before it comes to a rest?
A.50m
B.80m
C.180m
D.200m
E.300m
列算式thx
1 Answer
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- Prof. PhysicsLv 71 decade agoFavorite Answer
You have some information missing. How much does its velocity decrease?
As far as I remember this question, the velocity should decrease from 30 m/s to 20 m/s in 100 m.
So, I will use this to do the question.
Initial velocity, u = 30 m/s
Final velocity, v = 20 m/s
Distance, s = 100 m
By v2 = u2 - 2as
(20)2 = (30)2 - 2a(100)
Deceleration, a = 2.5 ms-2
Now, initial velocity, u = 20 m/s
Final velocity, v = 0
By v2 = u2 - 2as
0 = (20)2 - 2(2.5)s
Further distance, s = 80 m
So, the answer is B.
Source(s): Physics king
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