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# how do i begin this chemistry problem?

What mass of titanium(IV) chloride could be formed from the reaction of 3.00 g titanium and 8.00 grams of chlorine gas (Cl2)?

### 4 Answers

- 1 decade agoFavorite Answer
Nater Tater is completely incorrect.

You are looking for the amount of a substance you can make only using what you're given.

You will require 2 equations. 1 per element.

The Balanced Equation is Ti + 2Cl2 = TiCl4

First take the 3g of Titanium and find how much Ti(IV)Cl can be made using this equation.

3g Ti x (1 mole Ti / 47.90g Ti) x (1 mole TiCl4 / 1 mole Ti) x (142g TiCl4 / 1 Mole TiCl4) =

Thats how many grams of TiCl4 can be made from 3 g of Titanium

Next you do the same thing with Chlorine.

8g Cl x (1 mole Cl / 35.5g Cl) x (1 mole TiCl4 / 1 mole Cl) x (142g TiCl4 / 1 Mole TiCl4) =

That's how many grams of TiCl4 you can make from 8 g of Chlorine.

Whichever one produces less is the maximum amount you can make using 3g of Ti and 8 grams of Cl

- Anonymous1 decade ago
8 + 3 = 11g titanium chloride. its that simple

- ?Lv 71 decade ago
Ti(s) + 2Cl2(g) ---------> TiCl4

moles of Ti = 3/ 47.867 =0.0627

which needs 0.125 moles of Cl2 for a complete reaction but we have

moles of Cl2 = 8/71 = 0.112 so chlorine is the limiting reagent and forms

0.112 /2 moles of TiCl4 = 0.0563 moles

or 0.0563* 189.71 g = 10.68 g

- Anonymous4 years ago
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